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Calculus Tool

Intermediate Value Theorem Calculator

Free Intermediate Value Theorem calculator for checking theorem conditions, finding roots, and verifying value existence with step-by-step solutionsfor calculus and mathematical analysis. Perfect for students learning continuity and root-finding.

Last updated: December 15, 2024

Three calculation types: theorem check, root finding, value existence
Continuity verification and bisection method
Step-by-step solutions with formulas

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Intermediate Value Theorem Calculator
Check theorem conditions, find roots, and verify value existence

Intermediate Value Theorem Results

Theorem Applies:

Yes

Intermediate Value Theorem Check

Formula: f(a) < k < f(b) or f(b) < k < f(a)

f(a):

-2.000

f(b):

2.000

Root Exists:

Yes

Step-by-Step Solution:

Step 1: Given parameters
Function: f(x) = x² - 2
Interval: [0, 2]
Target value: k = 0
Step 2: Check continuity
f(x) = x² - 2 is continuous on [0, 2]
Step 3: Calculate f(a) and f(b)
f(0) = -2.000
f(2) = 2.000
Step 4: Apply Intermediate Value Theorem
Since f(0) = -2.000 &lt; 0 &lt; 2.000 = f(2),
there exists c ∈ (0, 2) such that f(c) = 0
Step 5: Conclusion
The theorem applies: solution exists in the interval

Intermediate Value Theorem Tips:

  • • Function must be continuous on [a, b]
  • • f(a) and f(b) must have opposite signs for root finding
  • • k must be between f(a) and f(b) for value existence
  • • Theorem guarantees existence, not uniqueness
  • • Works for any continuous function

Intermediate Value Theorem Types

Theorem Check
Verify IVT conditions

Condition

f(a) < k < f(b) or f(b) < k < f(a)

Check if theorem applies to guarantee solution existence

Root Finding
Find approximate roots

Method

Bisection method approximation

Use IVT to find roots when f(a) and f(b) have opposite signs

Value Existence
Check if value exists

Condition

k between f(a) and f(b)

Verify if a specific value can be achieved in the interval

Temperature Analysis
Physics applications

Example

Temperature reaches every value between two points

Proving temperature continuity in physical systems

Population Dynamics
Biological applications

Example

Population reaches intermediate values

Modeling population growth and decay processes

Economics
Supply and demand analysis

Example

Supply and demand curves intersect

Proving market equilibrium exists

Quick Example Result

Intermediate Value Theorem with f(x) = x² - 2, [0, 2], k = 0:

Theorem Applies

Yes

f(0)

-2.000

f(2)

2.000

How to Calculate Intermediate Value Theorem

The Intermediate Value Theorem is a fundamental principle in calculus that guarantees the existence of solutions under certain conditions. Understanding this theorem is essential for calculus, mathematical analysis, and numerical methodswhere continuity and solution existence are important.

The Intermediate Value Theorem Process

Step 1: Identify the function f(x) and interval [a, b]
Step 2: Check continuity of f on [a, b]
Step 3: Calculate f(a) and f(b)
Step 4: Check if target value k is between f(a) and f(b)
Step 5: Apply the theorem to conclude existence

This systematic approach ensures accurate Intermediate Value Theorem calculations for any continuous function.

Intermediate Value Theorem Conditions

The theorem requires two main conditions: 1) The function f must be continuous on the closed interval [a, b], and 2) The target value k must be between f(a) and f(b). If both conditions are met, then there exists at least one number c in the open interval (a, b) such that f(c) = k. The theorem guarantees existence but not uniqueness of solutions.

  • Continuity: f must be continuous on [a, b]
  • Bracketing: f(a) < k < f(b) or f(b) < k < f(a)
  • Existence: ∃c ∈ (a, b) such that f(c) = k
  • Uniqueness: Not guaranteed by the theorem
  • Root Finding: f(a) and f(b) have opposite signs

Sources & References

  • Calculus: Early Transcendentals - James StewartComprehensive coverage of calculus including Intermediate Value Theorem
  • Introduction to Real Analysis - Robert G. Bartle, Donald R. SherbertRigorous treatment of continuity and Intermediate Value Theorem
  • Khan Academy - Intermediate Value TheoremVideo tutorials and practice problems on continuity and IVT

Need help with other calculus topics? Check out our derivative calculator and concavity calculator.

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Intermediate Value Theorem Example

Step-by-Step Solution
Checking IVT conditions for f(x) = x² - 2, [0, 2], k = 0

Given Parameters:

Function: f(x) = x² - 2

Interval: [0, 2]

Target value: k = 0

Calculation type: Theorem check

Solution Steps:

  1. Step 1: Given parameters
  2. Function: f(x) = x² - 2
  3. Interval: [0, 2]
  4. Target value: k = 0
  5. Step 2: Check continuity
  6. f(x) = x² - 2 is continuous on [0, 2]
  7. Step 3: Calculate f(a) and f(b)
  8. f(0) = -2.000
  9. f(2) = 2.000
  10. Step 4: Apply Intermediate Value Theorem
  11. Since f(0) = -2.000 &lt; 0 &lt; 2.000 = f(2),
  12. there exists c ∈ (0, 2) such that f(c) = 0
  13. Step 5: Conclusion
  14. The theorem applies: solution exists in the interval

Final Results:

Theorem Applies

Yes

Root Exists

Yes

f(0)

-2.000

f(2)

2.000

Root Finding

f(x) = x³ - 3x + 1, [0, 2], k = 0

Root exists: c ≈ 1.532

Value Existence

f(x) = sin(x), [0, π], k = 0.5

Value exists: c ≈ 0.524

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